[Schematron] How to find the inscope default namespace

[Rick Jelliffe]

Does anyone have any code for the following, for XSLT?

I want to find out for some element node, what the current default 
namespace URI is.

NOTE: I don't want to *set* the default namespace. I don't want to *set* 
the default namespace for Qnames.  I want to *get* the default namespace.

Furthermore, I don't want to use namespace nodes, since that is 
implementation dependent.

The reason is because of the XSD to Schematron converter: base type 
derivation uses the default namespace declarations. Anyone who thinks 
that namespace declarations are easier than using real attributes are 
invited to put their code where their mouth is :-)

Cheers
Rick Jelliffe